n, m = map(int, input().split())
a = list(map(int, input().split()))
counts = [0 for i in range(n)]
for i in range(n):
counts[i] = a.count(i+1)
print(min(counts))
#include <bits/stdc++.h>
using namespace std;
int freq[1000+1];
int main()
{
int n,k;cin>>n>>k;
int a[k];
for(int i=0;i<k;i++)
{
cin>>a[i];
freq[a[i]-1]++;
}
sort(freq,freq+n);
cout<<freq[0];
}
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